详细计算y=(x+1)sin2x+cos^4(3x+5)的导数
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方法/步骤
一阶导数计算:
∵y=(x+1)sin2x+cos^4(3x+5)
∴dy/dx
=sin2x+2(x+1)cos2x+4cos^3(3x+5)*[-sin(3x+5)]*3
=sin2x+2(x+1)cos2x-12cos^3(3x+5)*sin(3x+5).
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二阶导数计算:
dy/dx=sin2x+2(x+1)cos2x-12cos^3(3x+5)*sin(3x+5).
再次求导,即可计算二阶导数,有:
d^2y/dx^2
=2cos2x+2cos2x-4(x+1)sin2x+108cos^2(3x+5)sin^2(3x+5)-36cos^3(3x+5)cos(3x+5)
=4cos2x-4(x+1)sin2x+108cos^2 (3x+5)[1-cos^2(3x+5)]-36cos^4(3x+5)
=4cos2x-4(x+1)sin2x+108cos^2 (3x+5)-108cos^4(3x+5)]-36cos^4(3x+5)
=4cos2x-4(x+1)sin2x+108cos^2 (3x+5)-144cos^4(3x+5).
三阶导数计算:
对二阶导数d^2y/dx^2再次对自变量x求导,则:
d^3y/dx^3
=-8sin2x-4sin2x-8(x+1)cos2x-648cos(3x+5)sin(3x+5)+1728cos^3(3x+5)sin(3x+5)
=-12sin2x-8(x+1)cos2x+27cos(3x+5)sin(3x+5)[64cos^2(3x+5)-24].
END
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