已知z=f(10xy,x^2+y^2,4x^3)求z二阶偏导数步骤
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方法/步骤
一阶偏导数计算:
z=f(10xy,x^2+y^2,4x^3),用全微分求导法,则有:
dz=10f1'(ydx+xdy)+f2'(2xdx+2ydy)+12x^2f3'dx,即:
dz=10yf1'dx+10xf1'dy+2xf2'dx+2yf2'dy+12x^2f3'dx,
dz=(10yf1'+2xf2'+12x^2f3')dx+(10xf1'+2yf2')dy。
则z对x的一阶偏导数为:
=10yf1'+2xf2'+12x^2f3';
同理,z对y的一阶偏导数为:
=10xf1'+2yf2'。
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二阶偏导数求解:
因为=10yf1'+2xf2'+12x^2f3',再次对x求导,
所以
=10y(f11''*10y+f12''*2x+12x^2f13'')+2f2'+2x(f21''10y+f22''*2x+12x^2f23'')+24xf3'+12x^2(f31''10y+f32''*2x+12x^2f33''),
=100y^2f11''+40xyf12''+120yx^2f13''+2f2'+4x^2f22''+24x^3f23''+24xf3'+120yx^2f31''+24x^3f32''+144x^4f33'',
=100y^2f11''+40xyf12''+24yx^2f13''+2f2'+4x^2f22''+48x^3f23''+24xf3'+144x^4f33''
因为=10xf1'+2yf2',再次对y求导,
所以
=10x(f11''*10x+f12''*2y+f13''*0)+2f2'+2y(f21''*10x+f22''*2y+f23''*0)
=100x^2f11''+20xyf12''+2f2'+20xyf12''+4y^2f22'',
=100x^2f11''+40xyf12''+2f2'+4y^2f22''.
因为=10xf1'+2yf2',再次对x求导,
所以
=10f1'+10x(f11''*10y+f12''*2x+12x^2f13'')+2y(f21''*10y+f22''*2x+12x^2f23'')
=10f1'+100xyf11''+20x^2f12''+120x^3f13''+20y^2f12''+4xyf22''+24yx^2f23'',
=10f1'+100xyf11''+20(1x^2+y^2)f12''+120x^3f13''+4xyf22''+24yx^2f23''。
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